# Exercise 14.3.5

Suggest modifications to the interval-tree procedures to support the new operation

`INTERVAL-SEARCH-EXACTLY(T, i)`

, where $T$ is an interval tree and $i$ is an interval. The operation should return a pointer to a node $x$ in $T$ such that $x.int.low = i.low$ and $x.int.high = i.high$, or $T.nil$ if $T$ contains no such code. All operations including`INTERVAL-SEARCH-EXACTLY`

should run in $\O(\lg n)$ time on a $n$-node interval tree.

This only presents a problem if there are intervals with matching $low$ values – otherwise, it's just a basic binary tree search, looking at $low$ for the key. The solutions of the previous exercises assume that the low endpoints are distinct, so they even provide a function like that.

Assuming that we're not creating a multiset, that is, each interval can be present only once, the trick here is to define a total order on the intervals – $i_1 < i_2$ if and only if $(i_1.low, i_1.high) < (i_2.low, i_2.high)$ where the comparison is "lexicographical". That is, as long as two intervals have different lower bounds, the one that goes more to the left is smaller. If their lower bounds match, the one that has less width is the smaller.

With the ordering defined like that, we simply do a regular search in a BST.