# Exercise 12.3.3

We can sort a given set of $n$ numbers by first building a binary search tree containing these numbers (using

`TREE-INSERT`

repeatedly to insert the numbers one by one) and then printing the numbers by an inorder tree walk. What are the worst-case and best-case running times for this sorting algorithm?

The worst case is going to be $\Theta(n^2)$, which will be achieved if we insert elements in decreasing or increasing order. On each step we will need to walk what is essentially a linked list and append at it's end. That will perform $\sum_{i=1}^{n} i = n(n + 1)/2 = \Theta(n^2)$ operations.

In the best case we will insert each node at the highest level that has at least empty position. We can then insert 1 element with 1 operation, 2 elements with 2 operations, 4 elements with 3 operations, 8 elements with 4 operations and so on. This is the well-known $\Theta(n \lg n)$.

If we slightly modify our algorithm to be able to insert directly at the root, we can achieve this in linear time, but only if we are already inserting the elements in sorted order.